프로그래밍_일반/백준
boj 9610
Spadework
2020. 2. 6. 10:24
* Solved 기준 브론즈3 단순 풀이
l,a = [0]*4,0
for _ in range(int(input())):
x,y = map(int, input().split())
if(x == 0 or y == 0): a += 1
else: l[0 if x>0 and y>0 else 1 if x<0 and y>0 else 2 if x<0 and y<0 else 3] += 1
for i in range(4): print('Q{}: {}'.format(i+1, l[i]))
print('AXIS:', a)